Bug 1007140

Summary:	python (2.7) cannot identify the opensuse tumbelweed distribution
Product:	[openSUSE] openSUSE Tumbleweed	Reporter:	Forgotten User l1MoexVUtJ <forgotten_l1MoexVUtJ>
Component:	Development	Assignee:	Jan Matejek <jmatejek>
Status:	RESOLVED DUPLICATE	QA Contact:	E-mail List <qa-bugs>
Severity:	Normal
Priority:	P5 - None
Version:	Current
Target Milestone:	---
Hardware:	Other
OS:	Other
Whiteboard:
Found By:	---	Services Priority:
Business Priority:		Blocker:	---
Marketing QA Status:	---	IT Deployment:	---

Description Forgotten User l1MoexVUtJ 2016-10-27 01:20:08 UTC

In my tumbleweed install there is a file `/etc/SUSE-brand` but no `/etc/SuSE-release`. The latter is used by python 2.7 at least to identify the distribution python is running on. For example:
$ python
Python 2.7.12 (default, Jun 28 2016, 06:57:42) [GCC] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import platform
>>> platform.linux_distribution()
('', '', '')

If I link SUSE-brand to SuSE-release:
$  python
Python 2.7.12 (default, Jun 28 2016, 06:57:42) [GCC] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> import platform
>>> platform.linux_distribution()
('SuSE', 'openSUSE', '')

This is important for software like cobbler (for which there is a rpm in tumbleweed, did anyone even test that it could be started?), which relies on this particular call as well as the SuSE-release file presence to identify the right default for the service (such as what is the apache2 user).

Comment 1 Jan Matejek 2017-03-29 11:56:41 UTC

known problem

*** This bug has been marked as a duplicate of bug 997614 ***